Example to display image using Servlet

In this example, we are using FileInputStream class to read image and ServletOutputStream class for writing this image content as a response. To make the performance faster, we have used BufferedInputStream and BufferedOutputStream class.

You need to use the content type image/jpeg.

In this example, we are assuming that you have java.jpg image inside the c:\test directory. You may change the location accordingly.

To create this application, we have created three files:

1. index.html
2. DisplayImage.java
3. web.xml

---

index.html

This file creates a link that invokes the servlet. The url-pattern of the servlet is servlet1.

<a href="servlet1">click for photo</a>  

---

DisplayImage.java

This servlet class reads the image from the mentioned directory and writes the content in the response object using ServletOutputStream and BufferedOutputStream classes.

package com.javatpoint;  
import java.io.*;  
import javax.servlet.*;  
import javax.servlet.http.*;  
public class DisplayImage extends HttpServlet {  
 
    public void doGet(HttpServletRequest request,HttpServletResponse response)  
             throws IOException  
    {
    response.setContentType("image/jpeg");  
    ServletOutputStream out;
    out = response.getOutputStream();
    FileInputStream fin = new FileInputStream("c:\\test\\java.jpg");  
     
    BufferedInputStream bin = new BufferedInputStream(fin);  
    BufferedOutputStream bout = new BufferedOutputStream(out);  
    int ch =0; ;  
    while((ch=bin.read())!=-1)  
    {
    bout.write(ch);
    }
     
    bin.close();
    fin.close();
    bout.close();
    out.close();
    }
}